Reference Variables & Typecasting in C++

 #include<iostream>

using namespace std;

int c = 45; //Global Variable

int main()

{

    // ****************Built in data types******************

    // int a,b,c;

    // cout<<"Enter the value of a : "<<endl;

    // cin>>a;

    // cout<<"Enter the value of b : "<<endl;

    // cin>>b;

    // c = a+b;

    // cout<<"The sum is : "<<c<<endl;

    // cout<<"The global c is : "<<::c;    //Global Variable

    // *****************float,double and long double literals*****************

    // float d=34.4;

    // long double e = 34.4;

    //By default, "34.4" will be considered as double, not float

    //But "34.4f" will be considered as float

    //"34.4l" will be considered as long double

    // cout<<"The size of 34.4 is "<<sizeof(34.4)<<endl;

    // cout<<"The size of 34.4f is "<<sizeof(34.4f)<<endl;

    // cout<<"The size of 34.4F is "<<sizeof(34.4F)<<endl;

    // cout<<"The size of 34.4l is "<<sizeof(34.4l)<<endl;

    // cout<<"The size of 34.4L is "<<sizeof(34.4L)<<endl;

    // cout<<"The value of d is "<<d<<endl<<"The value of e is "<<e;

    // ******************Reference variables*******************

    // float x = 455;

    // float &y = x;

    // cout<<x<<endl;

    // cout<<y<<endl;

    // *******************Typecasting********************

    int a=45;

    float b = 45.46;

    cout<<"The value of a is : "<<(float)a<<endl;   //Both are same

    cout<<"The value of a is : "<<float(a)<<endl;

    cout<<"The value of b is : "<<(int)b<<endl;

    cout<<"The value of b is : "<<int(b)<<endl;

    int c = int(b);

    cout<<"The expression is "<<a + b<<endl;

    cout<<"The expression is "<<a + int(b)<<endl;

    cout<<"The expression is "<<a + (int)b<<endl;

    return 0;

}

OUTPUT:

> cd "d:\C++\" ; if ($?) { g++ tut7.cpp -o tut7 } ; if ($?) { .\tut7 } The value of a is : 45 The value of a is : 45 The value of b is : 45 The value of b is : 45 The expression is 90.46 The expression is 90 The expression is 90 PS D:\C++>